(3x)^2=1215

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Solution for (3x)^2=1215 equation: 



(3x)^2=1215

We move all terms to the left:

(3x)^2-(1215)=0

a = 3; b = 0; c = -1215;
Δ = b2-4ac
Δ = 02-4·3·(-1215)
Δ = 14580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:


$\sqrt{\Delta}=\sqrt{14580}=\sqrt{2916*5}=\sqrt{2916}*\sqrt{5}=54\sqrt{5}$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-54\sqrt{5}}{2*3}=\frac{0-54\sqrt{5}}{6}
=-\frac{54\sqrt{5}}{6}
=-9\sqrt{5}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+54\sqrt{5}}{2*3}=\frac{0+54\sqrt{5}}{6}
=\frac{54\sqrt{5}}{6}
=9\sqrt{5}
$

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